I hope you don't mind if I try again,
The weight of the residue collected to the weight of the final product is one thing I missed, sorry.
1198.4 ppm is 1198.4g cyclohexene/1,000,000g = x/.158g, where .158g is the total weight of the residue and x is the weight of cyclohexene in the .158g collection sample which I'm assuming is the entire mass of the residue collected. x = .000189347g
.000189347g/319.5g = .000000592g of cyclohexene per gram of my oil, or 592 ppb
(where 319.5g is the amount of BHO I'd get at 71 cans times 4.5g per can)
Maybe this time...
HMK, I don't see benzamide at 2981.5 ppm on the analysis print out...
2981.5/1,000,000 = x/.158 x = .000471077g of benzamide in the total residue sample.
.000471077g/319.5g = .000001474g of benzamide in each gram of my oil, or 1.474 ppm
If you divide the .000471077g by 568g (71 cans times 8 grams) you get .000000829g of benzamide in each gram of Graywolf's BHO, or .829 ppm, as he said a few posts back...
I'm sorry, but Graywolf confused me with this, "The first thing to keep in perspective, is that the total oil was 12 ppm from 21.3 liters, so the PPM in the study should be divided by 1,000,000 and multiplied by .000,012, to get the concentration.
That concentration number X 1,000,000 will give you parts per millionth."
so I tried figuring it out on my own.....
I divide the ppm results from the analysis by 319.5 grams (71 cans times 4.5g equals 319.5 grams) to get diluted ppm figures. For instance, cyclohexene shown with 1198.4 ppm would be at 3.75 ppm in my BHO. Your residual would be at approximately half that (2.1 ppm) since you get more (8 grams instead of 4.5 grams) BHO per can.
The ppms of the sample sent for analysis is a proportion, the only adjustment necessary is for dilution.
http://en.wikipedia.org/wiki/Parts_per_million
The weight of the residue collected to the weight of the final product is one thing I missed, sorry.
1198.4 ppm is 1198.4g cyclohexene/1,000,000g = x/.158g, where .158g is the total weight of the residue and x is the weight of cyclohexene in the .158g collection sample which I'm assuming is the entire mass of the residue collected. x = .000189347g
.000189347g/319.5g = .000000592g of cyclohexene per gram of my oil, or 592 ppb
(where 319.5g is the amount of BHO I'd get at 71 cans times 4.5g per can)
Maybe this time...
HMK, I don't see benzamide at 2981.5 ppm on the analysis print out...
2981.5/1,000,000 = x/.158 x = .000471077g of benzamide in the total residue sample.
.000471077g/319.5g = .000001474g of benzamide in each gram of my oil, or 1.474 ppm
If you divide the .000471077g by 568g (71 cans times 8 grams) you get .000000829g of benzamide in each gram of Graywolf's BHO, or .829 ppm, as he said a few posts back...
I'm sorry, but Graywolf confused me with this, "The first thing to keep in perspective, is that the total oil was 12 ppm from 21.3 liters, so the PPM in the study should be divided by 1,000,000 and multiplied by .000,012, to get the concentration.
That concentration number X 1,000,000 will give you parts per millionth."
so I tried figuring it out on my own.....