[river rat01]

if you were to try and figure out how many wpsf were in the various vert sys., how would you measure it?

lets go with a 1000w light in its optimun footprint.

lets say that you have a cylinder that is 3 feet tall, and has a circumfrence of 10 feet. = 30 square feet.
33wpsf?


or, would you count the square footage of the volume inside the cylinder?
3 feet dia.-3 feet tall = 9 square feet.
111wpsf?

[C21H30O2]

growing area will be the circumference of the growing cylinder 2*pi*r

[magiccannabus]

Yeah imagine the cylinder turned on it's side and rolled out flat. That's your surface area. It can be a real pain to get it tweaked though. Your best bet is to try to calculate how many foot-candles intensity you have at the various points around your growing area. As long as you don't exceed 70,000 anywhere you should be fine. If it's getting higher than that you may sunburn them no matter how much air you blow across them. Realistically you should aim for 30-50k as a maximum intensity at your expected canopy top. Aim to distribute about that intensity over as much space as evenly as you can. It's easier to reach those intensities with HID, but it's easier to have even distribution with fluorescents. There's always compromises to be made in this.

[river rat01]

mmm..pi.

well i'm not very good at spherical geometry so you "mathy" guys will have to help me along.

ok, so with a 1000w that has 140,000 lumens divided by the surface area of 30 feet gives me about 5000 lumens psf. thats no where near the 50,000 your saying that i need, magiccannabus.

so what size cylinder would be best for a 1000w sodium to be placed in the center?

[00420]

Pi = 3.14
r = 3'
H = 4'

2 x 3.14 = 6.28 X 3 = 18.84 x 4 = 75.36sqft /1k = 13.26wpsqft

I Belive this is right all double check when I get home ....
This would be for a 6 foot round 4 foot tall colisum type grow area I would cut it down to 3 foot on the hight n get up too 22-24wpsqft that's about where I'm at n I have no prob's

lighting conversion data
https://www.icmag.com/ic/showthread.php?t=108993

volume=the number of units that can be arranged to completely fill the space within the object.

volume of a cylinder:
v=bh
=(pi*radius sq)(h) edit: pi times radius squared times height=volume

1k w/ out cool tubes w/ blower/10-18" fan underneath, directing heat upwards+out.
vegetables will grow in to (very close) to light. tomatoes permitted to grow as close to illumination as possible. w/in 3-6".
take into account lateral heat dissipation if no cool tubes used.
higher temps accelerate metabolism of plants - as long as other environmentals are w/in parameters, cylindrical-type air flow are points to take note of.
important (debatable) to measure par (photosynthetically active radiation) as well.
practice run(s) w/out vegetables+mock routine maintenance activities w/in area, w/ temp+rh readings more considerations.
1k, whether mh/hps will illuminate approx. nine cu ft thoroughly from one ft away.
draw 1 ft circumference around bulb(s) as reference point/line of perimeter w/ greatest illumination points around light(s). moves veggies back as maturation progresses (stretch) and attempt to create circular canopy using 1 ft circumference line as target imaginary line.

actual formula:

n=desired light level in lux*surface area/effective flux[lumens]

where n is the number of fixtures required to achieve desired lux

example: 9'x128'(252 feet of area) table-area over which 400w hps' will hang. light intensity of 8600 lux(800 foot candles) is desired.
effective flux(lumens) is ~38,400 lumens.
the number(n) of fixtures is equal to the light level times the surface area to be lighted divided by the effective flux, or

(800*9*128)/38,400=24 fixtures

the fixture pattern is defined by the horizontal spacing and the height above the crop surface (or, in this case, the concave curvature of the imaginary 1 ft circumference around the 1k hung vert).

the light level is equal to the effective flux divided by the area, or,

e=f/a [and, therefor, a=f/e]

where e is the light level, f the effective flux (lumens), and a the area

full sunlight=~2000 umol/sq m/sec - ~450 par watts/sq m (400-700nm)=5000 lumens=50,000 lux ['umol' is micro-moles. mole is quantity of substance that contains same number of ultimate particles as is contained in 12g of carbon-12, or avogadro's number, 6.0228x10^23]

~photon (par) saturation point: 300 par watts upon leaf surface/3000 lumens of full spectrum(mercury vapor+incandescent+uvb+cmh+hps +sulphur/etc).

1k hps ~ 5000 lumens @ 1 ft/~250 par watts

1k mh ~ 133 par watts @ 1ft (due to lack of par colors, standing alone)

pyranometer-measures photons between 400-1100nm.

~ 20 photons required to make/store 1 molecule of sugar.

note: sunmaster warm deluxe states 345 par watts.

[river rat01]

is all this shit gonna be on the test?