So lets go ahead and knock out the exchangeable cations, Ca, Mg and K. Your Na is in the lowish range of acceptable so we are going to ignore it.
First the formula to calculate lbs per acre is the tcec x % of the cation you want x Meq for that cation. Meq for Ca is 400, for Mg 240 and for K 780.
So for the traditional Albrecht ratio...68% Ca, 12% Mg and 5% K. Your tcec is 17.74 so here are the calcs for how many lbs per acre you would want if you pick the traditional Albrecht ratios:
Ca...0.68 x 400 x 17.74 (tcec) = 4825 lbs per acre...and for some reason (I failed to notice earlier) logan has reported yours in ppm instead of lbs per acre...so 4825/2 =2412 ppm. You can see that is the desired value Logan reported...we, however, are going to work in lbs per acre...so 4825 lbs per acre.
Mg...0.12 x240 x 17.74 = 511 lbs per acre...255 ppm (again what Logan recommends)
K...0.05 x 780 x 17.74 = 691 lbs per acre... 345 ppm...so working backwards Logan is recommending 276 ppm x 2 = 552 lbs per acre/ 780x17.74 = 4% K saturation.
First the formula to calculate lbs per acre is the tcec x % of the cation you want x Meq for that cation. Meq for Ca is 400, for Mg 240 and for K 780.
So for the traditional Albrecht ratio...68% Ca, 12% Mg and 5% K. Your tcec is 17.74 so here are the calcs for how many lbs per acre you would want if you pick the traditional Albrecht ratios:
Ca...0.68 x 400 x 17.74 (tcec) = 4825 lbs per acre...and for some reason (I failed to notice earlier) logan has reported yours in ppm instead of lbs per acre...so 4825/2 =2412 ppm. You can see that is the desired value Logan reported...we, however, are going to work in lbs per acre...so 4825 lbs per acre.
Mg...0.12 x240 x 17.74 = 511 lbs per acre...255 ppm (again what Logan recommends)
K...0.05 x 780 x 17.74 = 691 lbs per acre... 345 ppm...so working backwards Logan is recommending 276 ppm x 2 = 552 lbs per acre/ 780x17.74 = 4% K saturation.